Question

36% of the maximum marks are required to pass a test. A student gets 123 marks and is declared failed by 39 marks. Find the maximum marks.

Answer 1

let total marks =x
ATQ,
36÷100×100=123+39=162
x=162×100÷36
x=450 answer

Answer 2

Let total marks =x
We are given that the marks of student is 123 and he fails by 39 marks thus =>
36% of x = 123+39
=162 marks
36/100*x=162
x= 162*100/36
x=450 marks