Question

36. One mole of an ideal gas expands at a
constant temperature of 300 K from an
initial volume of 10 litres to a final volume
of 20 litres. The work done in expanding
the gas is (R=8.31J/mole-K)​

Answer 1

Answer:

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Answer 2

The work done in expanding is 1.728 KJ .

Given :

Temperature of system , T = 300 K .

Initial volume , $V_i=10\ liters$ .

Final volume , $V_f=20\ liters$ .

We know , work done at constant temperature is given by :

$W=nRT \ ln\dfrac{V_f}{V_i}$

Putting all values in above equation we get :

$W=1 \times 8.31\times 300 \times \ ln\dfrac{20}{10}\\W=1728\ J\\W=1.728\ KJ$

Hence , this is the required solution .

Learn More :

Thermodynamics

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