Question

36. Solubility product of
Agcl
is 2.0x10-10 mol2 dm-6
Maximum concentration of Ag- ions in the solution is:
2.0x10-12 mol dm-3
1.4x10-12 mol dm-3
1.0x10-12 mol dm-3
2.5x10-10 moldm
​

Answer 1

Explanation:

solubility product for AgCl = [Ag+]×[Cl-]

2.0×10^(-10) mol² dm^(-6) = [Ag+] × [Cl-]

[Ag+] = 2.0×10^(-10) ÷ [Cl-] mol dm^(-3)

here, concentration of Cl ion , i.e., [Cl-] , is that given in solutions ( whose value has not been given here)

put the value of [Cl-] , u will get your answer