36. The displacement of a particle executing S.H.M. is given by x = a sin(π/6t)+bcos(π/6t)
a = 3 cm and b = 4 cm. Find the amplitude and initial phase of S.H.M.
Answers
Answered by
0
Answer:
Given,
Position function, X=Asin(πt+ϕ)......(1)
Velocity function, v=dtdX=Aπcos(πt+ϕ)........(2)
Condition, (at t=0, velocity v=πcms−1 andx=1cm )
From equation (1), 1=Asin(π×0+ϕ)......(3)
From equation (2), π=Aπcos(π×0+ϕ)........(4)
From (3) and (4)
tanϕ=1⇒ϕ=π/4
Put value in equation (3)
1=Asin(π×0+π/4)=Asin(π/4)
A=2cm
Hence, amplitude is 2cm and phase is 4π
Similar questions