Physics, asked by Anjali3009, 9 months ago

36.
The equivalent capacitance between points A and
B of the circuit shown will be:​

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Answered by syed2020ashaels
0

Answer:

The equivalent capacitance between points A and B of the circuit shown will be \frac{8}{3}μF.

Explanation:

capacitance, a property of an electric conductor or set of conductors that is measured by the amount of separate electric charge that can be stored on it per unit change in electric potential. Capacity also implies associated electrical energy storage. If an electric charge is transferred between two initially uncharged conductors, they both become equally charged, one positive, the other negative, and a potential difference is created between them. Capacitance C is the ratio of the amount of charge q on each conductor to the potential difference V between the conductors, or simply C = q/V.

In both practical and meter–kilogram–second scientific systems, the unit of electric charge is the coulomb and the unit of potential difference is the volt, so the unit of capacity—called a farad (symbolized F)—is one coulomb. per volt. One farad is an extremely large capacitance. Commonly used convenient subdivisions are one-millionth of a farad, called a microfarad (μF), and one-millionth of a microfarad, called a picofarad (pF; older term, micromicrofarad, μμF). In the electrostatic system of units, capacitance has the dimensions of distance.

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