Question

36. The quartile deviation of a normal distribution with mean 10 and SD 4 is
(a) 0.675.
(b) 67.50.
(c) 2.70.
(d) 3.20.
given by

explain the steps ​

Answer 1

.As always QD=0.675SD

So here the value f sd= 4

Thn 0.675*4=2.70