36. The sum of the digits of a two digit number is 15. If the number formed by reversing the digits is
less than the original number by 27. Find the original number
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15
Answer:
Number = 96
Reversed = 69
Step-by-step explanation:
Let the number be ab.
( where a is the tens digit and b is the unit one )
Original number (equation) = 10a + b_(1
we have given that their sum is 15. so,
a + b = 15
a = 15 - b_(2
Now, reversed number (eq) = 10b + a_(3
Original no. = Reversed no. + 27 (given
10a + b = (10b + a) + 27 [eq1 = 27 +eq3]
(substituting the eq 3 here)
10(15 - b) + b = (10b + 15-b) + 27
150 - 10b + b = 9b + 42
108 = 18b
6 = b
a = 15 - b (eq2
a = 15 - 6
a = 9
hence, the original number is 96.
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