36. The sum of three consecutive integers is 48. What are these integers?
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Answer:
Let,
The three consecutive integer = x, x+ 1 , x+ 2
x, x+1, x+2= 48
x + x+ 1 + x+2 = 48
3x+ 3 = 48
3x = 48 - 3
3x = 4 5
x = 45 / 3
x= 15
So
The three consecutive integer
x, x + 1 , x+ 2
15 15 +1 15 + 2
16 17
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