Question

36. The wavelength of an electromagnetic radiation with
energy 3.3 x 10^(-12) erg is
(1) 8000 A
(2) 6000 Å
(3) 4000 A
(4) 5000 A​

Answer 1

Answer:

Answer:lamda=6000A

Frequency(f)=velocity(c)/lamda

F=speed of light/lamba

F=3×10^8/6000×10^-10

=0.5×10^15hz

F=5×10^14hz

Energy=hf

h=Planck constant

=6.63×10^-34×5×10^-14

E=3.315×10^-47J