Question

36. Two balls are projected vertically upward direction
with same speed 60 m/s at an interval of 2 s. The
time from the projection of the second body after
they will meet is (take g = 10 m/s2]
(1) 5 s
(2) 6 s
(3) 75
(4) 8 5​

Answer 1

Answer:

8s

Explanation:

Starting with t = 0 when 1st ball is thrown.

H1 = 60t - 5t^2 , So you will get 2 values of t for same H (one going up and one coming down) since it is quadratic.

Time for second ball = t -2

H2 = 60(t-2) - 5(t-2)^2

For balls to meet H1 = H2

60t - 5t^2 = 60(t-2) - 5(t-2)^2

Solving, we get t = 10s

We started t=0 from throwing 1st ball, so time from projection of second ball = 10 - 2 = 8s

Answer 2

Answer:

5s is answer be reveal tower in sevorel in prouusys