Math, asked by kaartikeyat80, 4 months ago


36. Two water taps running together can fill a tank in 3*1/13 hours. If one tap takes 3 hours
more than the other to fill the tank, then how much time will each tap take to fill the
tank?

Answers

Answered by devpichy
1

Answer:

One tap takes 5 hrs and another 8 hrs separately to fill the tank

Step-by-step explanation:

Let one tap fill the tank in x hrs.  

Therefore, other tap fills the tank in (x + 3) hrs.  

Work done by both the taps in one hour is  

1/x + 1/(x+3) = 13/40  

(2x + 3)40 = 13(x2 + 3x)  

13x2 – 41x – 120 = 0  

(13x + 24)(x – 5) = 0  

x = 5 (rejecting the negative value)  

Hence, one tap takes 5 hrs and another 8 hrs separately to fill the tank.

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