Question

36)
What is width of 10 interference fringes in a young's double slit experiment? When the double slit
separation is 1.5mm and the screen is 2m away. The wavelength of light used is 600nm. Also find the
change in fringe width when the apparatus is dipped in a liquid of R.I.
3​

Answer 1

Answer:

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Answer 2

Given:

d = 1.5nm

D = 2nm

λ = 6000nm

n = 3

To find:

The width and the change in fringe when the apparatus is dipped in a liquid of R.I.3

Solution:

• β = ($\frac{D}{d}$)λ

β = 6000 × $\frac{1,5}{2}$

β = 6000 × 0.75

β = 4500m

• βˣ = β×$\frac{1}{x}$      (x = μ)

βˣ = $\frac{4500}{3}$

βˣ = 1500m