Question

36. Write the properties of carbon compounds. Give the IUPAC name of following compounds.
(i) CH3 - CH2 - CH2 - CO-OH
(ii) CH3 - CH2 - CH2 - CH2 - OH
(III) CH3 - CH2- CH2 - CH2 - CHO
(III) CH2 = CH - C = CH​

Answer 1

Explanation:

1. butanoic acid

2.butanol

3.pentanl

4.but - 1,3- di- ene

Answer 2

Answer:

▪ Carbon compounds are formed by sharing electrons, thus they form covalent bonds.

▪ Carbon compounds have low intermolecular force.

▪ Carbon compounds have low melting and boiling points.

IUPAC names:

(i) Functional group: Carboxylic acid (double bonded O and OH)

It has 4 carbon atoms.

Thus, name: Butan-oic acid = Butanoic acid

(ii) Functional group: Alcohol (OH)

It has 4 carbon atoms.

Thus, name: Butan-ol = Butanol

(iii) Functional group: Ketone (when you will draw the structure, you will find double bonded O)

It has 5 carbon atoms.

Thus, name: Pentan-one = Pentanone

(iv) Functional group: Alkyne

It has 4 carbon atoms and a double and triple bond on the 1st and 3rd carbon atom respectively.

Thus, name: Butan-yne = But-1-ene-3-yne

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