36. Write the relation for magnification of a (1) convex lens (ii) concave mirror.
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Consider a concave mirror and a convex lens (refractive index = 1.5) of focal length 10 cm each, separated by a distance of 50 cm in air (refractive index = 1) as shown in the figure. An object is placed at a distance of 15 cm from the mirror. Its erect image formed by this combination has magnification M1. When the set-up is kept in a medium of refractive index 7/6, the magnification becomes M2. The magnitude ∣∣∣∣∣M1M2∣∣∣∣∣ is
7
The first image from reflection by spherical concave mirror can be found from mirror formula:
v1+u1=f1...(i)
For concave surface: u=-15 cm, f=-10 cm
Substituting in equation (i)
v1+−151=−101=v1=15010−15⇒v=−30cm
the magnification is given as m=−uv=−−15−30=7
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