Math, asked by jaswantu5826, 11 months ago

36 x square - 12ax+ a square minus b square is equals to zero find the value of x

Answers

Answered by himagrawal
2

Step-by-step explanation:

(6x-a)^2 - b^2 =0

(6x-a)^2 = b^2

6x-a = +b or - b

6x = a+b or a-b

X = (a+b)/6 or (a-b)/6

Hope it helps you. Mark it as a brainliest answer please

Answered by ubaidmuazzam
2
36x^2-12ax+(a^2-b^2)=0. ... (6x)² - 2.(6x).a + a² -b² = 0 {6x - a}² - b² = 0 use formula , a² -b² = (a - b)(a + b) {6x -a -b}{6x -a + b} =0 x = (a + b)/6 , (a ...
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