Question

360 ml of 1 M HCl solution is taken. Find the mass (in grams) of Calcium hydroxide required
to completely neutralize this HCl solution.​

Answer 1

Given :

Molarity of HCl solution = 1M

Volume of the solution = 360mL

To Find :

Mass of calcium hydroxide required to completely neutralize this HCl solution.

Solution :

■ First of all let's write chemical reaction :-

$\underline{\boxed{\bf{\orange{2HCl+Ca(OH)_2\:\longrightarrow\:CaCl_2+2H_2O}}}}$

As per chemical reaction,

• One mole of calcium hydroxide reacts with two moles of hydrochloric acid solution.

Mass of 1 mole of Ca(OH)₂ : 74g

Mass of 2 moles of HCl : 73g

■ Let's find mass of HCl present in the solution.

We know that

• molarity = mole/volume

⭆ 1 = mole/0.36 (L)

⭆ mole = 0.36

Mass of HCl present in the solution will be

• 0.36 × 36.5 = 13.14g

As per concept of stoichiometry;

74g of Ca(OH)₂ reacts with 73g of HCl solution

Therefore mass of Ca(OH)₂ required to react with 13.14g of HCl will be

➠ mass = 13.14 × 73/74

➠ mass = 13.14 × 0.986

➠ mass = 12.95g

Answer 2

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Given :

Molarity of HCl solution = 1M

Volume of the solution = 360mL

To Find :

Mass of calcium hydroxide required to completely neutralize this HCl solution.

Solution :

■ First of all let's write chemica reaction :-

2HCl+Ca(OH)₂ → CaCl₂+2H₂O

As per chemical reaction,

• One mole of calcium hydroxide reacts with two moles of hydrochloric acid solution.

Mass of 1 mole of Ca(OH)₂ : 74g

Mass of 2 moles of HCl : 73g

■ Let's find mass of HCl present in the solution.

We know that

• molarity = mole/volume

⭆ 1 = mole/0.36 (L)

⭆ mole = 0.36

Mass of HCl present in the solution will be

• 0.36 × 36.5 = 13.14g

As per concept of stoichiometry;

74g of Ca(OH)₂ reacts with 73g of HCl solution

Therefore mass of Ca(OH)₂ required to react with 13.14g of HCl will be

➠ mass = 13.14 × 73/74

➠ mass = 13.14 × 0.986

➠ mass = 12.95g