Question

(361)^3 + (139)^3 ÷ (361)^2 -(361×139) + (139)^2​

Answer 1

Let 361 = a, 139 = b

$= \frac{ {a}^{3} + {b}^{3} }{ {a}^{2} - ab + {b}^{2} }$

$= \frac{(a + b)( {a}^{2} - ab + {b}^{2} )}{( {a}^{2} - ab + {b}^{2}) }$

= ( a + b ) = 361 + 139 = 500

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