Question

366 rs....divided among A,B,C...A got 1/2(B+C) rs..
And B got 2/3 (A+C)...then find how much money A got...​

Answer 1

Answer:

A + B + C = 366

A = (B+C)/2

B = (A+C) * 2/3

2) isolate variables to get them all in terms of c

366 - b- c = (b+c)/2

732 - 2b -2c = b+c

732 - 3c = 3b

244 - c =b

244 - c = (a + c)(2/3)

366 - 3c/2 = a +c

366 - 5c/2 = a

3) plug back into equation 1 and solve for c

(366 - 5c/2) + (244 - c) + c = 366

244 - 5c/2 = 0

244 = 5c/2

488 = 5c

97.6 = c

4) now use c to solve for a and b

244 - 97.6 = b

146.4 = b

366 - 5(97.6)/2 = a

122 = a

5) check your answers in the original equations

122 + 146.4 + 97.6 = 366

366 = 366

122 = (146.4+97.6)/2

122 = 122

146.4 = (122+97.6) * 2/3

146.4 = 146.4

Step-by-step explanation: