Question

3699 when divided by a restain
number gives 231 as the
quotient and 3 as the
I remainder, find the number,​

Answer 1

Answer:

a=bq+r (by division algorithm)

Given a= 3699,b= ?, q=231 and r=3

So 3699= b×231 + 3

3699= 231b + 3

3699-3 = 231b

3696 = 231b

•

• • b= 3696/231 = 16 ans

Answer 2

Answer:

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