Question

36g of carbon and 128g of oxygen are mixed to produce carbon monoxide. calculate the amount of CO formed and also write the limiting reagent​

Answer 1

The balanced chemical equation for the reaction is :-

2C + O₂ → 2CO

Given that 36g of Carbon is mixed with 128g of Oxygen to produce Carbon Monoxide. And we have to calculate the amount of CO formed.

Number of moles in 36g of Carbon :-

= Given Mass/Molar mass

= 36/12

= 3 mole

Number of mole in 128g of O₂ :-

= Given Mass/Molar mass

= 128/32

= 4 mole

Here, we are given more moles of O₂, than of C. Thus, Carbon is the Limiting Reagent and will control the amount of product.

Now, from the reaction :-

∵ 24g of C → 56g of CO

∴ 36g of C → 36×56/24 = 84g CO

Thus, 84g of CO is formed.

Answer 2

Answer:

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