Question

36x^2 + 23 = 60x (Solve by Shree Dharacharya's formula)

Answer 1

36x² + 23 =60x
Or, 36x² - 60x +23 =0

Formula to be used :
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X = (- b ± (b²-4ac)^½)/2a
__________________
Here we go...
$x = \frac{ - ( - 60) - + \sqrt{ {( - 60)}^{2} - 4 \times 36 \times 23 } }{2 \times 36} \\ = \frac{60 + - \sqrt{3600 - 3312} }{2 \times 36} = \frac{60 + - \sqrt{288} }{72} \\so..either..x = \frac{60 - 16.97}{72} = \frac{43.03}{72} = 0.598...approx.. \\ or..x = \frac{60 + 16.97}{72} = \frac{76.97}{72} = 1.07...approx$
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Answer 2

Nice question mate!!!✌✌✌

Dharacharya's formula is same as quadratic formula.

Refer attachment for understanding the process.

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