Math, asked by prathama2201, 5 months ago

(36x^3)^1/3
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Answers

Answered by mahatokanchan915
0

Enter a problem...

Calculus Examples

Popular Problems Calculus Find the Critical Points 3x-36x^(1/3)

3

x

36

x

1

3

3x-36x13

Find the derivative.

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3

12

x

2

3

3-12x23

Set the derivative equal to

0

0.

3

12

x

2

3

=

0

3-12x23=0

Solve for

x

x.

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x

=

8

,

8

x=8,-8

Substitute the values of

x

x which cause the derivative to be

0

0 into the original function.

f

(

8

)

=

3

(

8

)

36

(

8

)

1

3

f(8)=3(8)-36(8)13

f

(

8

)

=

3

(

8

)

36

(

8

)

1

3

f(-8)=3(-8)-36(-8)13

Evaluate.

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f

(

8

)

=

48

f(8)=-48

f

(

8

)

=

48

f(-8)=48

Find the domain of the derivative.

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Interval Notation:

(

,

0

)

(

0

,

)

(-∞,0)∪(0,∞)

Set-Builder Notation:

{

x

|

x

Answered by sharanya4128
2

Answer:

(36×3) ×1/3=36

Step-by-step explanation:

Hope it helps u dear

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