Question

36x²-12ax+(a²-b²)=0
solve this question by quadratic formula {D=b²-4ac} & {x=[-b(+-)√D]/(2a)}.........
please solve this question.......​

Answer 1

Answer:

${36x}^{2} - 12ax + ( {a}^{2} - {b}^{2} ) = 0 \\ \\ using \: quadratic \: formula \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a} \: \: and \: \frac{ - b - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ \\ x = \frac{12 + \sqrt{144 - 4 \times 36( {a}^{2} - {b}^{2}) } }{2 \times 36} \: \: \: and \: \: \frac{12 - \sqrt{144 - 4 \times 36( {a}^{2} - {b}^{2} }) }{2 \times 36} \\ x = \frac{12 + \sqrt{144 {a}^{2} - 144 {a}^{2} + 144 {b}^{2} } }{72} and \: \: \frac{12 - \sqrt{144 {a}^{2} - 144 {a }^{2} + 144 {b}^{2} } }{72} \\ x = \frac{12 + \sqrt{144 {b}^{2} } }{72} and \: \frac{12 - \sqrt{144 {b}^{2} } }{72} \\ x = \frac{12 + 12b}{72} and \: \: \: \frac{12 - 12b}{72} \\ x = \frac{12(1 + b)}{72} and \: \frac{12(1 - b)}{72} \\ x = \frac{1 + b}{6} and \frac{1 - b}{6}$

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