Question

37*25=7,,,95*37=5,,,87*85=15,,,27*41=? explain​

Answer 1

Answer:

The required value is 0.

Explanation:

The given terms in a pattern are

37 * 25 = 7

95 * 37 = 5

87 * 85 = 15

We have to find the value for the term 27 * 41 following the same pattern.

37 * 25 = 7

⇒ 925 ( Product of 37 & 25 )

⇒ 9 + 2 + 5 ( Sum of digits )

⇒ 16

⇒ 16 - 9 ( Subtract 9 )

⇒ 7

Now,

95 * 37 = 5

⇒ 3515

⇒ 3 + 5 + 1 + 5

⇒ 14

⇒ 14 - 9

⇒ 5

Now,

87 * 85 = 15

⇒ 7395

⇒ 7 + 3 + 9 + 5

⇒ 24

⇒ 24 - 9

⇒ 15

The pattern followed by the given numbers is:

1. Take the product of two two-digit numbers.

2. Add the digits of the product number upto two digits.

3. Subtract 9 from the number obtained.

4. The final number is the required value.

By using this pattern, we get,

27 * 41

⇒ 1107

⇒ 1 + 1 + 0 + 7

⇒ 09

⇒ 09 - 9

⇒ 0

∴ 27 * 41 = 0

∴ The required value is 0.

Answer 2

Answer:

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LETS TRY TO ANSWER THIS

LETS TRY TO ANSWER THISFIRST OF ALL FIND THE LOGIC BEHIND IT

LETS TRY TO ANSWER THISFIRST OF ALL FIND THE LOGIC BEHIND ITIF THE NUMBER ARE

LETS TRY TO ANSWER THISFIRST OF ALL FIND THE LOGIC BEHIND ITIF THE NUMBER ARELet a,b,c = d

• Then c×10 -(b-a)=d

Then c×10 -(b-a)=dso now going by this logic we have

• Then c×10 -(b-a)=dso now going by this logic we have1,5,8=76

• Then c×10 -(b-a)=dso now going by this logic we have1,5,8=768×10-(5–1) =76

• Then c×10 -(b-a)=dso now going by this logic we have1,5,8=768×10-(5–1) =762,7,3=25

• Then c×10 -(b-a)=dso now going by this logic we have1,5,8=768×10-(5–1) =762,7,3=253×10 -(7–2)=25

• Then c×10 -(b-a)=dso now going by this logic we have1,5,8=768×10-(5–1) =762,7,3=253×10 -(7–2)=253,4,9=89

• 9×10-(4–3)=89

• 9×10-(4–3)=894,5,7=69

• 9×10-(4–3)=894,5,7=697×10-(5–4)=69

9×10-(4–3)=894,5,7=697×10-(5–4)=69So, 5,3,8=????

• 9×10-(4–3)=894,5,7=697×10-(5–4)=69So, 5,3,8=????8×10-(3–5)=82

9×10-(4–3)=894,5,7=697×10-(5–4)=69So, 5,3,8=????8×10-(3–5)=82The answer is 82