Question

-37,-33,-29,...........to 12 term

Answer 1

Step-by-step explanation:

Heee a1=-37

a2=-33

a3=-29

Common difference (d) =a2-a1=-33+37=4

nth term=a+(n-1)d

12th term a12=-37+(12-1)4

=-37+44=7

Answer 2

a = 37

d = -33 -(-37) = 4

The sum of n terms of an AP is given by

$\large\sf{Sn=\frac{n}{2}(2a+(n-1)d)}$

$\large\sf{S12=\frac{12}{2}(2(37)+(12-1)4)}$

$\large\sf{S12=6(-74+44)}$

$\large\sf{S12=-180}$