37. A container contains 1601 pure organic acid. 'X'Iorganic acid is taken out
and 'Y' I water is added in the container. By this ratio between organic acid to
water becomes 8:1. After this 'X+5'l mixture taken out and '2Y' I water poured
in it, by this ratio concentration of organic acid in solution becomes 66%. Find
the value of 'X+Y'
3
a) 35
(b) 45
(c) 55
(d) 65
(e) None of the given options
30 e
9
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Answers
Given A container contains 160 L pure organic acid X' L organic acid is taken out and 'Y' L water is added in the containe
To find : Value of X + Y
Solution:
Acid = 160 L
X litre taken out
=> Acid = 160 - X L
Y Litre water added
=> Water = Y L
(160 - X )//Y = 8/1
=> 160 - X = 8Y
=> X = 160 - 8Y
X + 5 Litre Mixture taken out
=> Acid taken out = (8/9)(X + 5) & Water Taken out (1/9)(X + 5)
Water added = 2Y
Acid = 160 - X - (8/9)(X + 5)
= ( 1440 - 9X - 8X - 40)/9
= (1400 - 17X)/9
= (1400 - 17 (160 - 8Y) ) /9
= (136Y - 1320)/9
Total Solution = 160 - X + Y - X - 5 + 2Y
= 155 + 3Y - 2X
= 155 + 3Y - 2(160 - 8Y)
= 19Y - 165
Acid is 66 %
=> (136Y - 1320)/9 = (0.66)(19Y - 165)
=> 136Y - 1320 = 112.86Y - 980.1
=> 23.14Y = 339.9
=> Y = 14.69
X = 160 - 8Y = 42.49
X + Y = 57.18
if its 66.67% = (2/3) then
(136Y - 1320)/9 = (2/3)(19Y - 165)
=> 136Y - 1320 = 114Y - 990
=> 22Y = 330
=> Y = 15
X = 160 - 8Y =40
X + Y = 40 + 15 = 55 Litre
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