Question

37. A farmer has divided his field into three parts as in the figure. Ist part is used to take care of his cattles. While il and III are used to grow two different crops. Answer the following: i) How much area has been used to take care for cattles ? i) Are the two areas part II and part III equal? Justify. lii) What is the total area of the field? iv) What values of the farmer are depicted here ?​

Answer 1

Step-by-step explanation:

1. Area to care for cattles= Area of 1st part= 1/2 × Base × height = 1/2 × 10 × 60 = 300 m². 2. No area of second and third part is not equal. Area of second part is 10√37 m² and the area of third part is 4800 m² 3. It is a Quadrilateral so area of the field is equal to the area of three parts = 300 + 10√37 + 4800 = 5100 + 10√37 m². This is the answer of your question. PLEASE MARK ME AS BRAINLIEST ☺️

Answer 2

Answer:

(i) Area used to take care for cattle's$=300m^{2}$

(ii) Area of part I and part II are equal.

(iii) Total area of the field $=7500m^{2}$

(iv)Value of part I$=300m^{2}$

Value of part II$=3600 m^{2}$

Value of part III $=3600 m^{2}$

Step-by-step explanation:

It is given that a farmer has divided his field into three parts.

(i) Area used to take care of cattle is area of part I.

We can see in the figure that part I AED is a triangle.

Area of triangle $=\frac{1}{2} *base*height$

                          $=\frac{1}{2} *ED*AE$                  

                          $=\frac{1}{2}*10*60$

                          $=5*60=300m^{2}$

(ii) From the figure we can see that ABCD is a parallelogram.

Diagonal AC is dividing the parallelogram into two equal parts.

So we can say that area if ADC is equal to area of ABC.

Therefore, area of part II and part III are equal.

(iii) Total area of field is the sum of areas of parallelogram and area of triangle.

Area of parallelogram is the product of base and height.

Here, height of the parallelogram is equal to length of AE.

Area of parallelogram$=60*120=7200m^{2}$

Total area$=7200+300=7500m^{2}$

(iv) Farmer has divided field in three parts.

Value of part I$=300m^{2}$

Value of part II$=\frac{7200}{2}=3600 m^{2}$

Value of part III$=\frac{7200}{2}=3600 m^{2}$

To know more about area go to the following link

https://brainly.in/question/28136612

To know more about parallelogram go to the following link

https://brainly.in/question/777600

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