Physics, asked by shayandas606, 4 months ago

37. A helium(2 4He) nucleus travelling at a speed of 7.0 x
10^6 ms-1 strikes a gold (79 197Au) film. By considering
only the electrostatic repulsion, what is the closest
possible distance of approach between the helium and
gold nuclei ?​

Answers

Answered by bpranav506
2

good morning friend

have a nice day dear

Answered by SammitSubudhi
0

Answer:

6x10-19)]/5.5x10-13 = 6.6x10-14 m. This is well inside the atom but some eight nuclear diameters from the centre of the gold nucleus.

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