Question

37.) A man bought some oranges at 12 in a rupee and the same no.
8 in a rupee. He mixed all the oranges and sold at the rate of 10 in a rupee .Find his profit and loss %.​

Answer 1

Answer:

51.92%

Step-by-step explanation:

The man purchased 12 oranges for 1₹

So CP for this transaction is 1/12₹ per piece.

Now he made another purchase of 8 oranges for the same amout i.e. 1₹

So CP for this will be 1/8₹ per piece.

Total CP = 1/12 + 1/8 = (4+6)/48 = 10/48 = 5/24₹ per piece i.e. 0.208 CP [1]

Now SP for the same is 10 oranges for 1₹

So SP per piece is 1/10₹ i.e. 0.1 SP [2]

from 1&2

SP<CP so loss

loss% = loss*100/CP

= [(.208-0.1)*100]/0.208

= 10.8/0.208 = 51.92%