Question

37. A rope of length L is pulled by a
constant force F. The tension in the
rope at a distance x from the end where
the force is applied is
FL
F(L-x)
2)
L
Fx
3)
L-X
L-X
1)
FL
4)
​

Answer 1

EXPLANATION.

$\rm \to \: f \: = ma$

$\rm \to \: a \: = \frac{f}{m}$

$\rm \to \: \: mass \: \: per \: \: unit \: \: length \: = \lambda = \frac{m}{l}$

$\rm \to \: mass \: of \: part \: of \: length \: = (l - x) \: is$

$\rm \to \: \lambda \: = \frac{m}{(l \: - \: x)}$

$\rm \to \: m \: = \lambda \: (l - x)$

$\rm \to \therefore \: m \: = \frac{m(l - x)}{l}$

$\rm \to \: as \: we \: know \: that$

$\rm \to \: t \: = ma$

$\rm \to \: t \: = \frac{m(l - x)}{l} \times \frac{f}{m}$

$\rm \to \: t \: = \frac{f(l - x)}{l}$