Question

37. A toy is in the shape of a right circular cylinder with a hemisphere on one end and a
cone on the other. The height of the conical part is 1 cm less than the height of the
cylindrical part. The radii of the cylindrical, hemispherical and conical parts are equal
to 5 cm. Find the surface area of the toy, if the total height of the toy is 30 cm.
​

Answer 1

Total height= 30cm

height of cylinder=13cm

height of cone=30-18 (radius of hemisphere=height)

therefore height of cone= 12cm

C.S.A. of hemisphere:

2*22/7*5^2

=157.14 cm^2

C.S.A. of cylinder:

2*22/7*5*13

=408.571 cm^2

C.S.A of cone :

22/7*5*13

=204.28

Adding all C.S.As we get

 408.57

 204.28

+157.14

=769.99m^2 [Ans. =Surface area of toy]

Round of to 770 m^2.

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