Question

37. A toy is made in the shape of a cylinder with one hemisphere stuck to one end
and a cone to the other end, as shown in the figure, the length of the cylindrical
part of the toy is 20cm and its diameter is 10cm. If the slant height of the cone
is 13cm Find the surface area of the toy.
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Answer 1

Answer:

Surface area=πrl+2πrh+2πr².

πr(l+2h+r).

22/7(13+2*20+2).

22/7(13+42).

22/7*55.

172.857cm².

Answer 2

Answer:

[i] FOR COBILAT PORTION

r = 10/√2 25cm L = 13

[ii] FOR CYLINDRICAL PORTION

r = 10/2 = 25cm

[iii] FOR HEMISPHERE PORTION

r = 10/2 = 5cm

Surface area of the toy

= CSA of hemisphere + COSA of cylinder + CSA

of COSE

= 2π r2 + 2πthat + πr

= πr (2r + 2h + l)

= 22/7 x 5 (2x5 + 2x20+13)

= 22/7 x 5 (10+40+13)

= 22/7 x 5 x6/3 9

= 22x5x9 = 2990CM2

.:. surface area of toy is 2990CM2