37. Calculate self inductance of a coil when current in it changes by 2A in 10^2
seconds and emf
produced is 20 volts.
Answers
Answered by
1
E = Ldi/dt
20 = L 2/10²
L = 20*10²/2
L = 1000H
Answered by
1
We have to calculate the self inductance of a coil when current in it changes by 2 A in 10² seconds and end produced is 20 volts.
solution : induced emf is given by, E = L di/dt
here di/dt = 2A/10² sec = 0.02 A/sec
induced emf , E = 20 volts
so, 20 volts = L × 0.02 A sec
⇒20/0.02 = L
⇒L = 1000 H
Therefore the self inductance of the coil is 1000 Henry.
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