Question

37. Factorise 8p3 – 12p2q + 6pq? – q3​

Answer 1

Answer:

=(2p)3−(q)3−6pq(2p−q)

=(2p)3−(q)3−3(2p)(q)(2p−q)

Let a=2p= & b=q

So, 

(a)3−(b)3−3ab(a−b)

=(a−b)3

So, 

(2p)3−(q)3−3(2p)(q)(2p−q)=(2p−q)3

So, 

8p3−q3−12p2q+6pa2

=(2p−q)(2p−q)(2p−q)

Step-by-step explanation:

hope u understand

Answer 2

(6g)%=75:-4₹*-753₹":*764&+-=8&%:+