Question

37. If alpha and Beta are the zeroes of the quadratic polynomial p(x)=3.x^2 - 4x - 7. then find the
quadratic polynomial whose zeroes are
$\frac{1}{ \alpha } \: \: \frac{1}{ \beta }$
​

Answer 1

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Answer 2

Answer:

= 3x^2 -4x -7

= 3x^2 + 3x - 7x -7

= 3x ( x +1 ) -7 (x+1)

= (3x -7) (x+1)

= alpha = 3x-7

= beeta = x+1

1/alpha + 1/beeta = 1/3x-7 + 1/x+1