37. If n,, n, and n, are the fundamental frequencies of three
segments into which a string is divided, then the original
fundamental frequency n of the string is given by-
[AIPMT 2000, 2012, 2014]
1 1 1 1
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Explanation:
1n=1n1+1n2+1n3
1n−−√=1n−−√1+1n−−√2+1n−−√3
n−−√=n−−√1+n−−√2+n−−√3
n=n1+n2+n3`
Answer :
A
Total length of string l=l1+l2+l3
(as string is divided into three segments)
n1=12l1Tμ−−√,n2=12l2Tμ−−√,n3=12l3Tμ−−√
Hence frequency ∝1length(∵n=12lTm−−−√)
∴1n=2lTμ−−√=2l2Tμ−−√+2l3Tμ−−√=1n1+1n2+1n3
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......hope it helps :)
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