37. If sin theta = 1/√2 then (tan theta + cos theta) =
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sin theta= 1/ √2
if a right angle triangle is drawn we can see opposite side is 1 and hypotenuse is √2.
so the adjacent side is
(1*1)+ x^2= √2* √2
x= 1
so tan theta= opposite side/adjacent side
=1
cos theta= adjacent side / hypotenuse
1/√2
now,
tan theta + cos theta= 1+ 1/√2
=(2+√2)/2
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