Question

37) If the bus travels 50 km faster at the time of time reaching the destination, and if it goes at an average speed of 30 km per hour, it will reach 20 minutes late in the scheduled time, what is the distance to be cut?​

Answer 1

given datas are,

speed,s1=50

speed,s2=30

therefore,

Speed=s1+s2

=50+30

=80

time=20min

we know that,

speed=distance/time

distance= speed ×time

=80×20

=1600.Ans...

hope it help u

Answer 2

ur answer is 1600

hope it help u