Question

. 37) If the wind Velocity at height of 2m above ground is 5.o kmph, it's value of height of 9m above ground be expected to be in km/hr about​

Answer 1

Answer:

Yes, if for design purpose or you are looking for some empirical correlations, please have a look at ASHRAE handbook Section 16.3, Eq(4) (if I remember it correctly). It gives a correlation of wind speed at different heights

Answer 2

Given: The wind velocity at a height above $2m$ is $5km/hr$

To find: The velocity at a height of $9m$ above ground.

Solution:

We know that the formula for wind velocity is,

$v =Ch^{\frac{1}{7}}$

The power is 1/7 for the height level is below $500m$.

$h$ is the height and $C$ is the constant.

According to the question,

$5=C*2^{\frac{1}{7}}$ (for the height $2m$) (eq. 1)

$v=C*9^{\frac{1}{7}}$ (for the height of $9m$) (eq. 2)

On dividing the eq 1 by eq. 2 we get,

$\frac{5}{v}=(\frac{2}{9})^\frac{1}{7}$

⇒ $\frac{5}{v} = 0.80$

⇒ $v=\frac{5}{0.80}$

⇒ $v=6.198km/hr$

Final answer:

The value of the velocity at a height $9m$ above ground level is $6.198km/h$