Math, asked by tom77, 11 months ago

37. In a class of 80 students numbered 1 to 80,
all odd numbered students opt for Cricket,
student whose numbers are divisible by 5
opt for Football and those whose numbers
are divisible by 7 opt for Hockey. The
number of students who do not opt any of
the three games, is
(a) 13
(b) 24
(c) 28✓
(d) 52​

Answers

Answered by emily365
1

Answer:

36

Step-by-step explanation:

total no. of students=80

no.of students who opted for cricket=80÷2=40

no.of students who opted for football=80÷5=16

no. of students who opted for hockey=77÷7=11 (nearest no. preceding 80 and divisible by7)

no.of students who opted for cricket and football=80÷(2×5)=8

no.of students who opted for cricket and hockey=70÷(7×2)=5 (nearest no. preceding 80 and divisible by7)

no.of students who opted for football and hockey=70÷(7×5)=2

no.of students who opted for all=70÷(7×5×2)=1

therefore seperating repeated students=(40+16+11)-(8+5+2)-3(1)=44(participants)

therefore who didn't participate=80-44=36

Answered by manan665
3

Answer:

37. In a class of 80 students numbered 1 to 80,

all odd numbered students opt for Cricket,

student whose numbers are divisible by 5

opt for Football and those whose numbers

are divisible by 7 opt for Hockey. The

number of students who do not opt any of

the three games, is (c) 28 answer

Similar questions