Question

37. In a Young's double-slit experiment, the intensity of the
central maximum is I. The width of one slit is now doubled.
The intensity at the point where the intensity was originally
0.5 I, will now be
(1) 0.75 1.
(2) 1.
(3) 1.51
(4) None of these​

Answer 1

Answer:

ANSWER

Central max intensity =I

0

β=

d

λD

Y=

4d

λD

Δx=

D

Yd

⇒Δx=

4dD

λDd

=

4

λ

∅=

λ

2π

×

4

λ

=

2

π

I=I

1

+I

2

+2

I

1

I

2

cos∅

∅=0,I=I

0

,I

1

=I

2

=I

s

I

0

=4I

s

→(i)

nowlos∅=

2

π

⇒I=2I

s

→(ii)

∴from(i)+(ii),

I=

2

I

0