Question

37. In an exhibition hall, there are 24 display boards each of length in
50cm and breadth lm. There is a 100m long aluminium strip, which
is used to frame these boards. How many boards will be framed
using this strip? Find also the length of the aluminium strip required
for the remaining boards.​

Answer 1

Explanation:

Given:

Total display boards = 24

Length of strip = 100 m

Length of one display board = 1 + 0.5

= 1.5 m

Breadth of one display board = 1 m

Perimeter of one display board = 2 × (l + b)

= 2 × (1.5 + 1)

= 5 m

Number of boards which will be framed = 100 / 5

= 20

Number of boards unframed = 24 – 20

= 4

Length of strip for required for remaining boards = 4 × Perimeter of one board

= 4 × 5

= 20 m.