Physics, asked by manishagolla, 9 months ago

37. In Fig, the magn
18. the magnetic needle has magnetic
moment .7*10- Am? and moment of inertia
7.5X10 kg ml. It performs 10 complete
Oscillations in 6.70 s. What is the magnitude of the
magnetic field?
1) 0.2 T
2) 0.05T
3) 0,08 T
4) 0.01T​

Answers

Answered by BubblySnowflake
2

As we learnt,

Time period of oscillating Bar magnet -

T=2\pi\sqrt\frac{I}{MB}

Wherein,

I = moment of inertia = 7.5*10

M = magnetic moment = 7*10

T = time taken = 6.7

B = magnetic field = ?

6.7=2\pi\sqrt\frac{7.5*10}{7*10*B}

\frac{6.7}{2\pi}=\sqrt\frac{7.5*10}{7*10*B}

\frac{{6.7}^{2}}{{2}^{2}*{\pi}^{2}}=\frac{7.5*10}{7*10*B}

B=\frac{7.5*10*4}{6.7*6.7*\pi*\pi*7*10}

\bold{B=0.01T}

Here π = 22/7

So, Option (D) is correct.

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