Question

37. In which of the following equilibrium K and K, are
not equal?
[AIPMT (Prelims)-2010]
(1) 2NO(g) = N2 (9) + O2 (g)
(2) SO, (g) + NO2 (9) — SO2 (g) + NO(g)
(3) H2(g) + 12 (9) — 2HI(g)
(4) 2C(s) + 02 (9) 200 (9)​

Answer 1

Answer:

4

Explanation:

becuase Kp=Kc+∆ngRT

in 4 value of ∆ng is 1but in other this is zero so Kp is not equal to Kc

Answer 2

Answer:

Option (4)

2C (s) + O2 (g) ---> 2CO2 (g)

We know,

Kp = Kc (RT)^(delta ng)

where, ng = no. of moles of gaseous (product) - no. of moles of gaseous (reactants)

Now,

in this example, No. of gaseous moles on the product side = 2 (2 moles of CO2)

and on the reactants side = 1 (only 1 mole of O2)

So, delta ng = 2 - 1 = 1

Now, that means,

Kp = Kc (RT)^1 = KcRT

So we can easily see that Kp is not equal to Kc but its equal to Kc × RT.

I hope you understood :)