Question

37. On Monday, there were thrice as many peanuts in Sack X as Sack Y. On Tuesday,
3952 peanuts in Sack X were sold. Now there were thrice as many peanuts in Sack
Y as Sack X. How many peanuts were there in Sack X at first?
A. 4644
B. 6644
C. 4446
D. 4466

pls answer in detail with full answer ​

Answer 1

Step-by-step explanation:

On Monday x = 3y (thrice as meany peanuts in sack x)

On Tuesday

(x-3952)*3 = y

Substitute for x from eq 1

(3y -3952)*3 = y

9y - 11856 = y

y = 1482

Then x = 3*y = 3*1482 = 4446

So there were 4446 peanuts in sack X

Answer 2

Answer:

Ans : c) 4446

Solu:

let the no of peanuts be x in SNACK X

And y in SNACK Y

GIVEN:

Monday: 3y=x => y=x/3

Tuesday: 3(x-3952)=y

=> 3x -11856 =x/3

9x-35568=x

8x = 35568

x =4446, y=1482

Therefore no of peanuts in SNACK X was 4446 and peanuts in y are 1482

Hence option c