Question

37) Person A and B travel from the same point. The person A moves 8 km to the s
turns at a 30 ° angle and goes north. Person B moves about x km towards east and turns ou
and heads towards north. Then find out, at what height the two men meet from the ongm,
and the distance traveled by person B before he turns to north.
5 X 1 = 5
38) A fox and an eagle lived at the top of a 6-meter-high cliff, at the foot of a cliff about 10
m away from a point A on the ground. The fox descended from the cliff and went straight to
point A. The eagle jumps vertically to a height x meters and then flies in a straight line to
point A, the distance traveled by each is the same. Find the value of x.
10mq​

Answer 1

Step-by-step explanation:

Given 37) Person A and B travel from the same point. The person A moves 8 km to the turns at a 30 ° angle and goes north. Person B moves    Both people  A and B travel from the same point and is found by tan theta = perpendicular / base

• So tan 30 = p / 8
• Or p = 0.5777 x 8
• Or p = 4.61 km
• Now the person travelled 8 km to south and made an angle 30 degree and turned north.  
• So distance travelled by the person b will be  
• Cos theta = base / hypotenuse
• Now cos 60 = 4.6 / q
• So 0.5 = 4.6 / q
• So q = 4.6 / 0.5
• Or q = 9.2 km
• So 9.2 + 4.6 = 13.8 km
• Therefore the total distance travelled by person b is 13.8 km and before he turned north he travelled 4.6 km

Given A fox and an eagle lived at the top of a 6-meter-high cliff, at the foot of a cliff about 10  m away from a point A on the ground. The fox descended from the cliff and went straight to  point A. The eagle jumps vertically to a height x meters and then flies in a straight line to  point A, the distance traveled by each is the same. Find the value of x.

• Height of the cliff is 6 m
• So distance between point and foot of the cliff is 10 m.
• Now fox and eagle will cover the same distance since the fox descends from the cliff and goes straight to point A.
• Now distance of eagle is height x m
• Also distance of the fox covered will be 6 + 10 = 16 m.
• Distance that eagle covered will be x + √(6 + x)^2 + 10^2
•   = x + √36 + 100 + 12 x + x^2
•   = x + √x^2 + 12 x + 136
• According to the question we get
• So x + √x^2 + 12 x + 136 = 16
• Or √x^2 + 12 x + 136 = 16 – x
• Squaring both sides we get
• So x^2 + 12 x + 136 = 16^2 + x^2 – 32 x
• 12 x + 136 = 256 – 32 x
• Or 44 x = 120
• Or x = 2.72

Reference link will be

https://brainly.in/question/6024132