Question

37) PV diagram of a diatomic gas is a straight
line passing through origin. The molar heat
capacity of the gas in the process wi
ll be​

Answer 1

Answer:

0

0

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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Critical Thinking

question_answer 1) P-V diagram of a diatomic gas is a straight line passing through origin. The molar heat capacity of the gas in the process will be

A) 4 R

B) 2.5 R

C) 3 R

D) \[\frac{4R}{3}\]

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Correct Answer: C

Solution :

P-V diagram of the gas is a straight line passing through origin. Hence \[P\propto V\] or \[P{{V}^{-1}}=\] constant Molar heat capacity in the process \[P{{V}^{x}}=\text{constant is }\] \[C=\frac{R}{\gamma -1}+\frac{R}{1-x}\]; Here \[\gamma =1.4\] (For diatomic gas) Þ \[C=\frac{R}{1.4-1}+\frac{R}{1+1}\] Þ \[C=3R\]

Answer 2

PV diagram of a diatomic gas being a straight line passing through origin,pressure will be proportional to volume.

• P∝V
• $\frac{P}{V}$=constant
• Molar heat capacity is defined as the amount of heat required to rise the temperature of one mole of a substance by one kelvin
• molar heat capacity,c = (R/γ-1)+(R/1-x)  ,for $PV^{x}$ =constant
• For a diatomic molecule γ=1.4

• c=$\frac{R}{1.4-1}$ + $\frac{R}{1+1}$

          =$\frac{10R}{4}$ + $\frac{R}{2}$

          =$\frac{12R}{4}$

          =3R