37. Refractive Index of the medium A relative to medium B is *
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Answer:
√6 / 3
Explanation:
Using snell's law,
n = sin i / sin r
n = sin 45° / sin 60°
we know that,
sin 45° = 1 / √2 and sin 60° = √3 / 2
∴ Using these values,
we get,
n = 1 / √2 ÷ √3 / 2 = √2 / √3
rationalising the denominator,
n = (√2 × √3) / (√3 × √3) = √6 / 3
∴ the refractive index is √6 / 3
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Answer:
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Explanation:
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