Question

37) The ages of A & B are in the ratio 3:5. Four years later, the sum of ages
is 48. Find their present ages​

Answer 1

Answer:

let their ages be x

A's age=3x

B's age=5x

after 4 years

A's age=3x+4

B's age= 5x+4

According to the question,

3x+4+5x+4=48

8x+8=48

8x=48-8

8x=40

x=40/8

x=5

present ages

A' age=3×5=15

B's age=5×5=25

Answer 2

Given -

• Ratio of their ages = 3:5

• Sum of their ages = 48

To find -

• Their present ages.

Solution -

Here, we are provided with the ratios of ages A & B, their after 4 years, the sum of their ages will be 48, and we need to find their present ages, for that, we will take a Common ratio, then we will make a linear equation.

So -

Let the Common ratio be x

3 = 3x

5 = 5x

After 4 years,

3 = 3x + 4

5 = 5x + 4

Now -

We will make a linear equation, and then we will transpose like terms together, and then we will find the value of x, from that we will get the present ages of A & B

On substituting the values -

$\longrightarrow$ (3x + 4) + (5x + 4) = 48

$\longrightarrow$3x + 5x + 4 + 4 = 48

$\longrightarrow$ 8x + 8 = 48

$\longrightarrow$ x = $\sf\dfrac{48 - 8}{8}$

$\longrightarrow$ x = $\sf\cancel{\dfrac{40}{8}}$

$\longrightarrow$ x = 5

At the end -

We will find their present ages, by multiplying 3 and 5 with 5, as it is the value of x.

on substituting the values -

3x = 3 × 5 = 15yrs

5x = 5 × 5 = 25yrs

$\therefore$ The present ages of A & B are 15yrs and 25yrs

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