Question

37.The term R ln KPo is equal​

Answer 1

Answer:

this is the write answer

Answer 2

The term R ln KPo is equal​ = 0.0831 bar.L/K.mol

• $Kp = Kc [RT]^{ng}$
• where, Kp and Kc are equilibrium constants.
• R is the gas constant.
• T is the temperature.

→The value of R (universal gas constant) ≈0.0831 bar.L/K.mol.

                                                                            ( P is in bar ).